Created for
Created by
if-then rules.
A decision tree progressively splits the training set into smaller and smaller subsets
"Divide and Conquer" Algorithm:
Which is the best split?
$${\displaystyle \mathrm {H} {(S)}=\sum _{x\in X}{-p(x)\log _{2}p(x)}}$$
$${\displaystyle \mathrm {H} {(S)}=\sum _{x\in X}{-p(x)\log _{2}p(x)}}$$
$${\displaystyle \mathrm {H} {(S)}=\sum _{x\in X}{-p(x)\log _{2}p(x)}}$$
$${\displaystyle \mathrm {H} {(S)}= {-p\log _{2}p} + {-q\log _{2}q} } $$
Decision Tree Solved | Id3 Algorithm (concept and numerical)| by Code Wrestling
These slides are based on
customised version of
framework